已知a,b,满足a(a+1)-(a²+2b)=1,求a²-4ab+4b²-2a+4b的值.
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已知a,b,满足a(a+1)-(a²+2b)=1,求a²-4ab+4b²-2a+4b的值.
已知a,b,满足a(a+1)-(a²+2b)=1,求a²-4ab+4b²-2a+4b的值.
已知a,b,满足a(a+1)-(a²+2b)=1,求a²-4ab+4b²-2a+4b的值.
a(a+1)-(a²+2b)=1即a²+a-a²-2b-1=0,即a-2b=1
a²-4ab+4b²-2a+4b=(a-2b)²-2(a-2b)=(a-2b)(a-2b-2)=1x(1-2)=-1
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