命题p:(x+1)²+y²>m²,q:(x-3)²+(y+3)²≤36,已知非q是p的充分不必要条件,求实数m的取值范围.重点是怎么解不等式,我有点忘记了,
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![命题p:(x+1)²+y²>m²,q:(x-3)²+(y+3)²≤36,已知非q是p的充分不必要条件,求实数m的取值范围.重点是怎么解不等式,我有点忘记了,](/uploads/image/z/1161077-5-7.jpg?t=%E5%91%BD%E9%A2%98p%EF%BC%9A%EF%BC%88x%2B1%29%26%23178%3B%2By%26%23178%3B%EF%BC%9Em%26%23178%3B%2Cq%EF%BC%9A%EF%BC%88x-3%EF%BC%89%26%23178%3B%2B%EF%BC%88y%2B3%EF%BC%89%26%23178%3B%E2%89%A436%2C%E5%B7%B2%E7%9F%A5%E9%9D%9Eq%E6%98%AFp%E7%9A%84%E5%85%85%E5%88%86%E4%B8%8D%E5%BF%85%E8%A6%81%E6%9D%A1%E4%BB%B6%2C%E6%B1%82%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4.%E9%87%8D%E7%82%B9%E6%98%AF%E6%80%8E%E4%B9%88%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%2C%E6%88%91%E6%9C%89%E7%82%B9%E5%BF%98%E8%AE%B0%E4%BA%86%2C)
命题p:(x+1)²+y²>m²,q:(x-3)²+(y+3)²≤36,已知非q是p的充分不必要条件,求实数m的取值范围.重点是怎么解不等式,我有点忘记了,
命题p:(x+1)²+y²>m²,q:(x-3)²+(y+3)²≤36,已知非q是p的充分不必要条件,求实数m的取值范围.
重点是怎么解不等式,我有点忘记了,
命题p:(x+1)²+y²>m²,q:(x-3)²+(y+3)²≤36,已知非q是p的充分不必要条件,求实数m的取值范围.重点是怎么解不等式,我有点忘记了,
p:圆心P(-1,0)半径m,取值圆外
q:圆心 Q(3.-3),r=6
非q是圆外的部分
PQ=√(16+9)=5
m≤r-PQ=1
m≤1