已知tan(π+α)=1/3 三角函数~已知tan(π+α)=1/3,求1/cos(-α)+sin(-α-90度)___________________________________________1/sin(540度-α)-cos(-α-270) 的值1/cos(-α)+sin(-α-90度)/1/cos(-α)+sin(-α-90度)
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![已知tan(π+α)=1/3 三角函数~已知tan(π+α)=1/3,求1/cos(-α)+sin(-α-90度)___________________________________________1/sin(540度-α)-cos(-α-270) 的值1/cos(-α)+sin(-α-90度)/1/cos(-α)+sin(-α-90度)](/uploads/image/z/12509617-49-7.jpg?t=%E5%B7%B2%E7%9F%A5tan%28%CF%80%2B%CE%B1%29%3D1%2F3+%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%7E%E5%B7%B2%E7%9F%A5tan%28%CF%80%2B%CE%B1%29%3D1%2F3%2C%E6%B1%821%2Fcos%28-%CE%B1%29%2Bsin%28-%CE%B1-90%E5%BA%A6%29___________________________________________1%2Fsin%28540%E5%BA%A6-%CE%B1%29-cos%28-%CE%B1-270%29+%E7%9A%84%E5%80%BC1%2Fcos%28-%CE%B1%29%2Bsin%28-%CE%B1-90%E5%BA%A6%29%2F1%2Fcos%28-%CE%B1%29%2Bsin%28-%CE%B1-90%E5%BA%A6%29)
已知tan(π+α)=1/3 三角函数~已知tan(π+α)=1/3,求1/cos(-α)+sin(-α-90度)___________________________________________1/sin(540度-α)-cos(-α-270) 的值1/cos(-α)+sin(-α-90度)/1/cos(-α)+sin(-α-90度)
已知tan(π+α)=1/3 三角函数~
已知tan(π+α)=1/3,求1/cos(-α)+sin(-α-90度)
___________________________________________
1/sin(540度-α)-cos(-α-270) 的值
1/cos(-α)+sin(-α-90度)/1/cos(-α)+sin(-α-90度)
已知tan(π+α)=1/3 三角函数~已知tan(π+α)=1/3,求1/cos(-α)+sin(-α-90度)___________________________________________1/sin(540度-α)-cos(-α-270) 的值1/cos(-α)+sin(-α-90度)/1/cos(-α)+sin(-α-90度)
tan(π+α) = tan(α) = 1/3
原式=1/cos(-α)+sin(-α-90度) * (sin(540度-α)-cos(-α-270))
=(sin(540度-α)-cos(-α-270)) / (cos(-α)+sin(-α-90度))
= (sin(α)+sin(α)) / (cos(α)+cos(α))
= sin(α)/cos(α) = 1/3
关於如何变换的,你就需要查看一下教材了,或是你Hi我(晚九点以后).
答案是1/27?