1+3=4=2^2,1+3+5=9=3^2...按此规律,试猜想:1+3+5+7...+(2N-5)+(2N-1)+(2N+1)的和是多少?
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![1+3=4=2^2,1+3+5=9=3^2...按此规律,试猜想:1+3+5+7...+(2N-5)+(2N-1)+(2N+1)的和是多少?](/uploads/image/z/12641879-47-9.jpg?t=1%2B3%3D4%3D2%5E2%2C1%2B3%2B5%3D9%3D3%5E2...%E6%8C%89%E6%AD%A4%E8%A7%84%E5%BE%8B%2C%E8%AF%95%E7%8C%9C%E6%83%B3%EF%BC%9A1%2B3%2B5%2B7...%2B%282N-5%29%2B%282N-1%29%2B%282N%2B1%29%E7%9A%84%E5%92%8C%E6%98%AF%E5%A4%9A%E5%B0%91%3F)
1+3=4=2^2,1+3+5=9=3^2...按此规律,试猜想:1+3+5+7...+(2N-5)+(2N-1)+(2N+1)的和是多少?
1+3=4=2^2,1+3+5=9=3^2...按此规律,试猜想:1+3+5+7...+(2N-5)+(2N-1)+(2N+1)的和是多少?
1+3=4=2^2,1+3+5=9=3^2...按此规律,试猜想:1+3+5+7...+(2N-5)+(2N-1)+(2N+1)的和是多少?
原式=[(2n+1+1)÷2]²
=(n+1)²
=n²+2n+1
(n+1)^2