已知α∈(π/2,π),sinα=3/5,则tan(α+π/4)等于?
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![已知α∈(π/2,π),sinα=3/5,则tan(α+π/4)等于?](/uploads/image/z/1332978-42-8.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%E2%88%88%EF%BC%88%CF%80%2F2%2C%CF%80%EF%BC%89%2Csin%CE%B1%3D3%2F5%2C%E5%88%99tan%EF%BC%88%CE%B1%EF%BC%8B%CF%80%2F4%EF%BC%89%E7%AD%89%E4%BA%8E%3F)
已知α∈(π/2,π),sinα=3/5,则tan(α+π/4)等于?
已知α∈(π/2,π),sinα=3/5,则tan(α+π/4)等于?
已知α∈(π/2,π),sinα=3/5,则tan(α+π/4)等于?
tan(α+π/4)=(tanα+tanπ/4)/(1-tanαtanπ/4)
其中tanα=3/4
所以原式=(3/4+1)/(1-3/4*1)=(7/4)/(1/4)=7