f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 14:02:54
![f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?](/uploads/image/z/13564871-71-1.jpg?t=f%28x%2B1%29%3Dx%5E2%2B2x%2B2%2C%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E8%AE%BEy%3Dx%2B1x%3Dy-1f%28x%2B1%29%3Dx%5E2%2B2x%2B2f%28y%29%3D%28y-1%29%5E2%2B2%28y-1%29%2B2f%EF%BC%88y%EF%BC%89%3Dy%5E2-2y%2B1%2B2y-2%2B2f%28y%29%3Dy%5E2%2B1f%28x%29%3Dx%5E2%2B1+++f%EF%BC%88y%EF%BC%89%3Dy%5E2-2y%2B1%2B2y-2%2B2%E6%80%8E%E6%A0%B7%E7%9A%84%E6%9D%A5%3F)
f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1
x=y-1
f(x+1)=x^2+2x+2
f(y)=(y-1)^2+2(y-1)+2
f(y)=y^2-2y+1+2y-2+2
f(y)=y^2+1
f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
f(y)=(y-1)^2+2(y-1)+2
=y^2-2y+1+2y-2+2
=y^2+1
f(x)满足:2f(x)-f(1/x)=x+1,求f(x)
设函数f(x)满足f(x)+2f(1/x)=x,求f(x)
已知f(x)满足2f(x)+f(1/x)=3x,求f(x)
F(X)满足F(x)+2f(x分之1)=3X,求f(x)
已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?
已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)
已知f(x)满足f(x)+2f(1/x)=3x,求f(x) ,
f(x)+f((x-1)/x)=2x; x!=0,1; 求f(x)
f(x)+f[(x-1)/x]=2x x不等于0,1.求f(x).
f(2x+1)=e^x,求f(x)
已知f(x+1)=x^2,求f(x)
2f(x^2)+f(1/x^2)=f(x),求f(x)
f(x-1)=2x/x-1求f(x)=?f(x+1)=?
已知2f(x)+f(1/x)=2x x#0 求f(x)
已知f(x)+2f(1/x)=x+2/x+3,求f(x)
若一次函数f(x) 满足f[f(x)]=1+2x 求f(x)
f(x)=x/(1+x^2)^0.5求f(f(f(x)))
设f(x)+f(x-1/x)=2x,求f(x)=?