已知x=根2-1 求(x+1/x²-x - x/x²-2x+1)÷1/x的值
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已知x=根2-1 求(x+1/x²-x - x/x²-2x+1)÷1/x的值
已知x=根2-1 求(x+1/x²-x - x/x²-2x+1)÷1/x的值
已知x=根2-1 求(x+1/x²-x - x/x²-2x+1)÷1/x的值
(x+1/x²-x - x/x²-2x+1)÷1/x
=(x²-1-x²/x(x-1)²)÷1/x
=-1/x(x-1)² *x
=-1/(x-1)²
=-1/(根号2-2 )²
=-1/6-4根号2
=-6-4根号2/4
=-3-2根号2/2