2/ab除以(1/a+1/b)+a^2+b^2/a^2+2ab+b^2
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2/ab除以(1/a+1/b)+a^2+b^2/a^2+2ab+b^2
2/ab除以(1/a+1/b)+a^2+b^2/a^2+2ab+b^2
2/ab除以(1/a+1/b)+a^2+b^2/a^2+2ab+b^2
=2/ab×ab/(a+b)+(a²+b²)/(a+b)²
=2/(a+b)+(a²+b²)/(a+b)²
=[2(a+b)+(a²+b²)]/(a+b)²
=(2a+2b+a²+b²)/(a+b)²