分解因式:x²-(2n+1)x+n²+n
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分解因式:x²-(2n+1)x+n²+n
分解因式:x²-(2n+1)x+n²+n
分解因式:x²-(2n+1)x+n²+n
x²-(2n+1)x+n²+n
=x²-(n+n+1)x+n(n+1)
=(x-n)[x-(n+1)]
=(x-n)(x-n-1)
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n²+n=(-n)[-(n+1)] ,-n-(n+1)=-(2n+1)
∴根据十字相乘法
x²-(2n+1)x+n²+n
=(x-n)(x-n-1)
解法2.
x²-(2n+1)x+n²+n
=x²-nx-(n+1)x+n(n+1)
=x(x-n)-(n+1)(x-n)
=(...
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n²+n=(-n)[-(n+1)] ,-n-(n+1)=-(2n+1)
∴根据十字相乘法
x²-(2n+1)x+n²+n
=(x-n)(x-n-1)
解法2.
x²-(2n+1)x+n²+n
=x²-nx-(n+1)x+n(n+1)
=x(x-n)-(n+1)(x-n)
=(x-n)(x-n-1)
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