若(1+X)²+Y+1的绝对值=0 则4x-3y分之2x-y等于?
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![若(1+X)²+Y+1的绝对值=0 则4x-3y分之2x-y等于?](/uploads/image/z/1615066-34-6.jpg?t=%E8%8B%A5%281%2BX%29%26%23178%3B%2BY%2B1%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D0+%E5%88%994x-3y%E5%88%86%E4%B9%8B2x-y%E7%AD%89%E4%BA%8E%3F)
若(1+X)²+Y+1的绝对值=0 则4x-3y分之2x-y等于?
若(1+X)²+Y+1的绝对值=0 则4x-3y分之2x-y等于?
若(1+X)²+Y+1的绝对值=0 则4x-3y分之2x-y等于?
∵(1+X)²+Y+1的绝对值=0
∴1+x=0 y+1=0
x=-1 y=-1
∴4x-3y分之2x-y=(-2+1)/(-4+3)=(-1)/(-1)=1