用lingo实现,y(i)=y(j)时,x(i)不等于x(j)?大哥大姐们:请问用lingo如何实现y(i)=y(j)时,x(i)不等于x(j)?lingo有这个功能吗?我试过了,但是不行,我的现有程序是:MODEL:data:M=7;enddatas
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 23:14:43
![用lingo实现,y(i)=y(j)时,x(i)不等于x(j)?大哥大姐们:请问用lingo如何实现y(i)=y(j)时,x(i)不等于x(j)?lingo有这个功能吗?我试过了,但是不行,我的现有程序是:MODEL:data:M=7;enddatas](/uploads/image/z/1804195-19-5.jpg?t=%E7%94%A8lingo%E5%AE%9E%E7%8E%B0%2Cy%EF%BC%88i%EF%BC%89%3Dy%EF%BC%88j%EF%BC%89%E6%97%B6%2Cx%EF%BC%88i%EF%BC%89%E4%B8%8D%E7%AD%89%E4%BA%8Ex%EF%BC%88j%EF%BC%89%3F%E5%A4%A7%E5%93%A5%E5%A4%A7%E5%A7%90%E4%BB%AC%EF%BC%9A%E8%AF%B7%E9%97%AE%E7%94%A8lingo%E5%A6%82%E4%BD%95%E5%AE%9E%E7%8E%B0y%EF%BC%88i%EF%BC%89%3Dy%EF%BC%88j%EF%BC%89%E6%97%B6%2Cx%EF%BC%88i%EF%BC%89%E4%B8%8D%E7%AD%89%E4%BA%8Ex%EF%BC%88j%EF%BC%89%3Flingo%E6%9C%89%E8%BF%99%E4%B8%AA%E5%8A%9F%E8%83%BD%E5%90%97%3F%E6%88%91%E8%AF%95%E8%BF%87%E4%BA%86%2C%E4%BD%86%E6%98%AF%E4%B8%8D%E8%A1%8C%2C%E6%88%91%E7%9A%84%E7%8E%B0%E6%9C%89%E7%A8%8B%E5%BA%8F%E6%98%AF%EF%BC%9AMODEL%3Adata%3AM%3D7%3Benddatas)
用lingo实现,y(i)=y(j)时,x(i)不等于x(j)?大哥大姐们:请问用lingo如何实现y(i)=y(j)时,x(i)不等于x(j)?lingo有这个功能吗?我试过了,但是不行,我的现有程序是:MODEL:data:M=7;enddatas
用lingo实现,y(i)=y(j)时,x(i)不等于x(j)?
大哥大姐们:
请问用lingo如何实现y(i)=y(j)时,x(i)不等于x(j)?
lingo有这个功能吗?
我试过了,但是不行,我的现有程序是:
MODEL:
data:
M=7;
enddata
sets:
demand/1..m/:p,a,d,x,y;
ob/1..m/:w;
endsets
data:
p=5,3,5,6,7,12,8;
a=3,4,4,1,5,8,8;
d=5,6,6,3,7,9,10;
enddata
[OBJ] min=@sum(demand(i):2*@abs(x(i)-p(i))+3*@abs(y(i)-a(i)));
@for(demand(i):
y(i)>a(i);
y(i)1);
@for(demand(i):@gin(x(i)));
@for(demand(i):@gin(y(i)));
end
怎么用程序表示当y相同时,x不同?
用lingo实现,y(i)=y(j)时,x(i)不等于x(j)?大哥大姐们:请问用lingo如何实现y(i)=y(j)时,x(i)不等于x(j)?lingo有这个功能吗?我试过了,但是不行,我的现有程序是:MODEL:data:M=7;enddatas
改了一点,在逻辑上没有问题,但是就不是线性模型了,用全局最优器解.
你看看吧!
MODEL:
data:
M=7;
enddata
sets:
demand/1..m/:p,a,d,x,y;
ob/1..m/:w;
link(demand,demand):aa;
endsets
data:
p=5,3,5,6,7,12,8;
a=3,4,4,1,5,8,8;
d=5,6,6,3,7,9,10;
enddata
[OBJ] min=@sum(demand(i):2*@abs(x(i)-p(i))+3*@abs(y(i)-a(i)));
@for(demand(i):
y(i)>a(i);
y(i)1);
@for(demand(i):@gin(x(i)));
@for(demand(i):@gin(y(i)));
@for(demand(i):
@for(demand(j)|j #ne# i:x(i)+y(i)=x(j)+y(j)+aa(i,j)));
@for(demand(i):
@for(demand(j):@free(aa(i,j))));
@for(link:
@free(aa));
@for(link:aa*aa>0);
end