sin^2θ/sinθ-cosθ + cosθ/1-tanθ = sin^2θ/sinθ-cosθ + cosθ/1-(sinθ/cosθ)=(sin^2θ-cos^2θ)/sinθ-cosθ我就想问下最后那两步化简是怎样出来的,最好给一个补充我
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![sin^2θ/sinθ-cosθ + cosθ/1-tanθ = sin^2θ/sinθ-cosθ + cosθ/1-(sinθ/cosθ)=(sin^2θ-cos^2θ)/sinθ-cosθ我就想问下最后那两步化简是怎样出来的,最好给一个补充我](/uploads/image/z/2088391-31-1.jpg?t=sin%5E2%CE%B8%2Fsin%CE%B8-cos%CE%B8+%2B+cos%CE%B8%2F1-tan%CE%B8+%3D+sin%5E2%CE%B8%2Fsin%CE%B8-cos%CE%B8+%2B+cos%CE%B8%2F1-%28sin%CE%B8%2Fcos%CE%B8%29%3D%28sin%5E2%CE%B8-cos%5E2%CE%B8%29%2Fsin%CE%B8-cos%CE%B8%E6%88%91%E5%B0%B1%E6%83%B3%E9%97%AE%E4%B8%8B%E6%9C%80%E5%90%8E%E9%82%A3%E4%B8%A4%E6%AD%A5%E5%8C%96%E7%AE%80%E6%98%AF%E6%80%8E%E6%A0%B7%E5%87%BA%E6%9D%A5%E7%9A%84%2C%E6%9C%80%E5%A5%BD%E7%BB%99%E4%B8%80%E4%B8%AA%E8%A1%A5%E5%85%85%E6%88%91)
sin^2θ/sinθ-cosθ + cosθ/1-tanθ = sin^2θ/sinθ-cosθ + cosθ/1-(sinθ/cosθ)=(sin^2θ-cos^2θ)/sinθ-cosθ我就想问下最后那两步化简是怎样出来的,最好给一个补充我
sin^2θ/sinθ-cosθ + cosθ/1-tanθ = sin^2θ/sinθ-cosθ + cosθ/1-(sinθ/cosθ)=(sin^2θ-cos^2θ)/sinθ-cosθ
我就想问下最后那两步化简是怎样出来的,最好给一个补充我
sin^2θ/sinθ-cosθ + cosθ/1-tanθ = sin^2θ/sinθ-cosθ + cosθ/1-(sinθ/cosθ)=(sin^2θ-cos^2θ)/sinθ-cosθ我就想问下最后那两步化简是怎样出来的,最好给一个补充我
第一个=后面是切割化弦,然后把分母全化成sinθ-cosθ ,通分就行了啦
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