通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)
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![通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)](/uploads/image/z/2109764-20-4.jpg?t=%E9%80%9A%E5%88%86x%2B4%2Fx%2Ax%2B4x%E4%B8%8Ex-5%2Fx%28x-5%29-2%28x-5%29)
通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)
通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)
通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)
不太明白你的意思,是二个多项式通分同分母吗?
(x+4)/(x^2+4x)
=(x+4)/[x(x+4)]
=1/x
=(x-2)/[x(x-2)
(x-5)/[x(x-5)-2(x-5)]
=(x-5)/[(x-5)(x-2)]
=1/(x-2)
=x/[x(x-2)]
这是算什么啊
x+4/x*x+4x,
=(x+4)/x(x+4)
=1/x
x-5/x(x-5)-2(x-5)
=1/x-2(x-5)
=(1-2x^2+10x)/x