将线段AB延长到C,使BC=1/3AB,反向延长AC到D点使AD=1/2AC,则CD=多少AB?
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![将线段AB延长到C,使BC=1/3AB,反向延长AC到D点使AD=1/2AC,则CD=多少AB?](/uploads/image/z/2354583-39-3.jpg?t=%E5%B0%86%E7%BA%BF%E6%AE%B5AB%E5%BB%B6%E9%95%BF%E5%88%B0C%2C%E4%BD%BFBC%3D1%2F3AB%2C%E5%8F%8D%E5%90%91%E5%BB%B6%E9%95%BFAC%E5%88%B0D%E7%82%B9%E4%BD%BFAD%3D1%2F2AC%2C%E5%88%99CD%3D%E5%A4%9A%E5%B0%91AB%3F)
将线段AB延长到C,使BC=1/3AB,反向延长AC到D点使AD=1/2AC,则CD=多少AB?
将线段AB延长到C,使BC=1/3AB,反向延长AC到D点使AD=1/2AC,则CD=多少AB?
将线段AB延长到C,使BC=1/3AB,反向延长AC到D点使AD=1/2AC,则CD=多少AB?
BC=1/3AB
AC=AB+BC=4/3AB
AD=1/2AC=(1/2)×(4/3AB)=2/3AB
CD=AD+AC
=2/3AB+2/3AB
=(2/3+4/3)AB
=2AB