已知函数f(x)在实数集中满足f(XY)=f(X)+f(y)且f(x)在定义域是减函数,1.求f(1)值,2.若f(2art
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 00:51:57
![已知函数f(x)在实数集中满足f(XY)=f(X)+f(y)且f(x)在定义域是减函数,1.求f(1)值,2.若f(2art](/uploads/image/z/3018077-53-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E5%AE%9E%E6%95%B0%E9%9B%86%E4%B8%AD%E6%BB%A1%E8%B6%B3f%28XY%29%3Df%28X%29%2Bf%28y%29%E4%B8%94f%28x%29%E5%9C%A8%E5%AE%9A%E4%B9%89%E5%9F%9F%E6%98%AF%E5%87%8F%E5%87%BD%E6%95%B0%2C1.%E6%B1%82f%281%29%E5%80%BC%2C2.%E8%8B%A5f%282art)
已知函数f(x)在实数集中满足f(XY)=f(X)+f(y)且f(x)在定义域是减函数,1.求f(1)值,2.若f(2art
已知函数f(x)在实数集中满足f(XY)=f(X)+f(y)且f(x)在定义域是减函数,1.求f(1)值,2.若f(2a
rt
已知函数f(x)在实数集中满足f(XY)=f(X)+f(y)且f(x)在定义域是减函数,1.求f(1)值,2.若f(2art
1.令x=1,y=1,得f(1)=f(1)+f(1),解得f(1)=0
f(1*1)=f(1)+f(1)推出f(1)=0
明显f(1*1)=f(1)+f(1)推出f(1)=0, 第二问不完整吧?