1.(x²+x)²-(x+1)² 2.2002²-2001*20033.(2+1)(2²+1)(2的四次方+1)...(2的2n次方+1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 12:56:26
![1.(x²+x)²-(x+1)² 2.2002²-2001*20033.(2+1)(2²+1)(2的四次方+1)...(2的2n次方+1)](/uploads/image/z/3763269-45-9.jpg?t=1.%28x%26%23178%3B%2Bx%29%26%23178%3B-%28x%2B1%29%26%23178%3B+2.2002%26%23178%3B-2001%2A20033.%EF%BC%882%2B1%EF%BC%89%EF%BC%882%26%23178%3B%2B1%EF%BC%89%EF%BC%882%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9%2B1%EF%BC%89...%EF%BC%882%E7%9A%842n%E6%AC%A1%E6%96%B9%2B1%EF%BC%89)
1.(x²+x)²-(x+1)² 2.2002²-2001*20033.(2+1)(2²+1)(2的四次方+1)...(2的2n次方+1)
1.(x²+x)²-(x+1)² 2.2002²-2001*2003
3.(2+1)(2²+1)(2的四次方+1)...(2的2n次方+1)
1.(x²+x)²-(x+1)² 2.2002²-2001*20033.(2+1)(2²+1)(2的四次方+1)...(2的2n次方+1)
1.x2+x)2-(x+1)2
=【x(x+1)】²-(x+1)²
=x²(x+1)²-(x+1)²
=(x+1)²(x²-1)
=(x+1)²(x+1)(x-1)
2.,20022-2001*2003
=(2001+1)(2003-1)-2001*2003
=2001*2003+2001+2003+1-2001*2003
=2001+2003+1
3.(2-1)(2+1)(2^2+1)(2^4+1).(2^(2n)+1)
=(2^2-1)(2^2+1)(2^4+1).(2^(2n)+1)
=(2^4-1)(2^4+1).(2^(2n)+1)
=[2^(2n)-1][2^(2n)+1]
=2^(4n)-1