(a²+2ab+b²)÷(a+b)= (4A²-9b²)÷(2A+3B)=若X+Y=5,xy=3 则X²Y+XY= X²Y+2X²Y平方+XY
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![(a²+2ab+b²)÷(a+b)= (4A²-9b²)÷(2A+3B)=若X+Y=5,xy=3 则X²Y+XY= X²Y+2X²Y平方+XY](/uploads/image/z/3815569-1-9.jpg?t=%28a%26%23178%3B%2B2ab%2Bb%26%23178%3B%EF%BC%89%C3%B7%EF%BC%88a%2Bb%29%3D+%EF%BC%884A%26%23178%3B-9b%26%23178%3B%EF%BC%89%C3%B7%EF%BC%882A%2B3B%EF%BC%89%3D%E8%8B%A5X%2BY%3D5%2Cxy%3D3+%E5%88%99X%26%23178%3BY%2BXY%3D+X%26%23178%3BY%2B2X%26%23178%3BY%E5%B9%B3%E6%96%B9%2BXY)
(a²+2ab+b²)÷(a+b)= (4A²-9b²)÷(2A+3B)=若X+Y=5,xy=3 则X²Y+XY= X²Y+2X²Y平方+XY
(a²+2ab+b²)÷(a+b)= (4A²-9b²)÷(2A+3B)=
若X+Y=5,xy=3 则X²Y+XY= X²Y+2X²Y平方+XY
(a²+2ab+b²)÷(a+b)= (4A²-9b²)÷(2A+3B)=若X+Y=5,xy=3 则X²Y+XY= X²Y+2X²Y平方+XY
1.(a+b)^2/(a+b)=a+b
2.(2A+3B)*(2A-3B)/(2A+3B)=2A-3B
3.根据题目求得x=(5+-根号13)/2,y=(5-+根号13)/2,然后求得结果,第4问也一样,结果自己算下吧,太难打了...