设a、b为实数,若(a²+b²)²-3(a²+b²)-10=0,求a²+b²的值速度aaaaa
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![设a、b为实数,若(a²+b²)²-3(a²+b²)-10=0,求a²+b²的值速度aaaaa](/uploads/image/z/3816368-8-8.jpg?t=%E8%AE%BEa%E3%80%81b%E4%B8%BA%E5%AE%9E%E6%95%B0%2C%E8%8B%A5%EF%BC%88a%26%23178%3B%2Bb%26%23178%3B%EF%BC%89%26%23178%3B-3%EF%BC%88a%26%23178%3B%2Bb%26%23178%3B%EF%BC%89-10%3D0%2C%E6%B1%82a%26%23178%3B%2Bb%26%23178%3B%E7%9A%84%E5%80%BC%E9%80%9F%E5%BA%A6aaaaa)
设a、b为实数,若(a²+b²)²-3(a²+b²)-10=0,求a²+b²的值速度aaaaa
设a、b为实数,若(a²+b²)²-3(a²+b²)-10=0,求a²+b²的值
速度aaaaa
设a、b为实数,若(a²+b²)²-3(a²+b²)-10=0,求a²+b²的值速度aaaaa
解析
令a²+b²=t
原式=t²-3t-10=0
(t-3/2)²-9/4-10=0
t1=5
t2=-2舍去,因为a²+b²>0
所以a²+b²=5
oh no
(a²+b²)²-3(a²+b²)-10=0
(a²+b²-5)(a²+b²+2)=0
a²+b²=5,或者,a²+b²= -2(舍掉)