化简求值 (x+1)²+(x-1)²-2(x+1)(x-1)其中x=-2013
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![化简求值 (x+1)²+(x-1)²-2(x+1)(x-1)其中x=-2013](/uploads/image/z/3999469-13-9.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC+%28x%2B1%29%26%23178%3B%2B%28x-1%29%26%23178%3B-2%28x%2B1%29%28x-1%29%E5%85%B6%E4%B8%ADx%3D-2013)
化简求值 (x+1)²+(x-1)²-2(x+1)(x-1)其中x=-2013
化简求值 (x+1)²+(x-1)²-2(x+1)(x-1)其中x=-2013
化简求值 (x+1)²+(x-1)²-2(x+1)(x-1)其中x=-2013
(x+1)²+(x-1)²-2(x+1)(x-1)=[(x+1)-(x-1)]²=2²=4
运用公式a²+b²-2ab=(a-b)²
(x+1)²+(x-1)²-2(x+1)(x-1)
=2(x+1)²-2(x+1)²
=0
x=-2013时,原式等于0
先用完全平方公式分解因式得到<(x+1)+(x-1)> ²=(2x)²当x=-2013时,原式=4026²