解方程:(1/x²+3x+2)+(1/x²+5x+6)+(1/x²+7x+12)+(1/x²+9x+20)=1/8
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 16:10:29
![解方程:(1/x²+3x+2)+(1/x²+5x+6)+(1/x²+7x+12)+(1/x²+9x+20)=1/8](/uploads/image/z/401938-34-8.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%3A%281%2Fx%26%23178%3B%2B3x%2B2%29%2B%281%2Fx%26%23178%3B%2B5x%2B6%29%2B%281%2Fx%26%23178%3B%2B7x%2B12%29%2B%281%2Fx%26%23178%3B%2B9x%2B20%29%3D1%2F8)
解方程:(1/x²+3x+2)+(1/x²+5x+6)+(1/x²+7x+12)+(1/x²+9x+20)=1/8
解方程:(1/x²+3x+2)+(1/x²+5x+6)+(1/x²+7x+12)+(1/x²+9x+20)=1/8
解方程:(1/x²+3x+2)+(1/x²+5x+6)+(1/x²+7x+12)+(1/x²+9x+20)=1/8
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=1/8
1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)=1/8
1/(x+1)-1/(x+5)=1/8
(x+5-x-1)/(x+1)(x+5)=1/8
32=x²+6x+5
x²+6x-27=0
(x+9)(x-3)=0
x=-9 x=3
检验:x=-9 x=3是方程的解