已知t²+t-1=0,则t³+2t²+2008=
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![已知t²+t-1=0,则t³+2t²+2008=](/uploads/image/z/5939534-38-4.jpg?t=%E5%B7%B2%E7%9F%A5t%26%23178%3B%2Bt-1%3D0%2C%E5%88%99t%26%23179%3B%2B2t%26%23178%3B%2B2008%3D)
已知t²+t-1=0,则t³+2t²+2008=
已知t²+t-1=0,则t³+2t²+2008=
已知t²+t-1=0,则t³+2t²+2008=
t²+t-1=0
t^2=-t+1
t^2+t=1
t³+2t²+2008
=t(-t+1)+2t²+2008
=t^2+t+2008
=2009
t²+t-1=0
t²+t=1
t³+2t²+2008
=t(t²+t+t)+2008
=t(1+t)+2008
=t²+t+2008
=1+2008
=2009
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t³+2t²+2008
=t(t²+t)+t²+2008
=t+t²+2008
=1+2008
=2009