方程m²/(x+2)-(x+5)/(x+2)=1/(x²-4)有增根,求m的值
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![方程m²/(x+2)-(x+5)/(x+2)=1/(x²-4)有增根,求m的值](/uploads/image/z/6898212-36-2.jpg?t=%E6%96%B9%E7%A8%8Bm%26%23178%3B%2F%28x%2B2%29-%28x%2B5%29%2F%28x%2B2%29%3D1%2F%28x%26%23178%3B-4%29%E6%9C%89%E5%A2%9E%E6%A0%B9%2C%E6%B1%82m%E7%9A%84%E5%80%BC)
方程m²/(x+2)-(x+5)/(x+2)=1/(x²-4)有增根,求m的值
方程m²/(x+2)-(x+5)/(x+2)=1/(x²-4)有增根,求m的值
方程m²/(x+2)-(x+5)/(x+2)=1/(x²-4)有增根,求m的值
两边乘(x+2)(x-2)
m²(x+2)-(x+5)(x-2)=1
增根则分母为0
x=2
代入m²(x+2)-(x+5)(x-2)=1
4m²=1
m=±1/2
x=-2
代入m²(x+2)-(x+5)(x-2)=1
1=1
和m无关
所以m=±1/2