A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
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![A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.](/uploads/image/z/7126071-15-1.jpg?t=A+paintball+with+a+mass+of+0.15kg+is+fired+from+a+paintball+gun+that+has+a+mass+of+5.5+kg.The+paintball+leaves+the+gun+with+a+velocity+of+45+m%2Fs+%5BN%5D+having+accelerated+for+0.10+s.Calculate+the+acceleration+and+the+final+velocity+of+the+paintball+gun.)
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
The original velocity is 0,so the a=v/t=450m/s`2
Acoording to the momentum theorem:m1×v1=m2×v2
so v2=0.15×45/5.5=1.23m/s
0.15kg的彩球,从质量为5.5kg的枪射出,加速0.10s后初速度是45m/s,计算加速度和枪的最终速度是多少。
这个可能是要用到动量定理:
m1 *V1=m2*V2 5.5* X=45*0.15 X=1.22
a=V/t= 45/0.10=450...
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0.15kg的彩球,从质量为5.5kg的枪射出,加速0.10s后初速度是45m/s,计算加速度和枪的最终速度是多少。
这个可能是要用到动量定理:
m1 *V1=m2*V2 5.5* X=45*0.15 X=1.22
a=V/t= 45/0.10=450
猜的,不知道对不对
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