已知函数f(x)的定义域为【0,1】,且同时满足:(1)对任意x∈【0,1】总有f(x)≥2(2)f(1)=3(3)若x1≥0,x2≥0,且x1+x2≤1,则有f(x1+x2)≥f(x1)+f(x2)-2前两问我都会.第一问求出来f(0)=2,第二问证
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![已知函数f(x)的定义域为【0,1】,且同时满足:(1)对任意x∈【0,1】总有f(x)≥2(2)f(1)=3(3)若x1≥0,x2≥0,且x1+x2≤1,则有f(x1+x2)≥f(x1)+f(x2)-2前两问我都会.第一问求出来f(0)=2,第二问证](/uploads/image/z/7635456-0-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%E3%80%900%2C1%E3%80%91%2C%E4%B8%94%E5%90%8C%E6%97%B6%E6%BB%A1%E8%B6%B3%EF%BC%9A%EF%BC%881%EF%BC%89%E5%AF%B9%E4%BB%BB%E6%84%8Fx%E2%88%88%E3%80%900%2C1%E3%80%91%E6%80%BB%E6%9C%89f%28x%EF%BC%89%E2%89%A52%EF%BC%882%EF%BC%89f%281%29%3D3%EF%BC%883%EF%BC%89%E8%8B%A5x1%E2%89%A50%2Cx2%E2%89%A50%2C%E4%B8%94x1%2Bx2%E2%89%A41%2C%E5%88%99%E6%9C%89f%28x1%2Bx2%29%E2%89%A5f%EF%BC%88x1%EF%BC%89%2Bf%28x2%29-2%E5%89%8D%E4%B8%A4%E9%97%AE%E6%88%91%E9%83%BD%E4%BC%9A.%E7%AC%AC%E4%B8%80%E9%97%AE%E6%B1%82%E5%87%BA%E6%9D%A5f%EF%BC%880%EF%BC%89%3D2%2C%E7%AC%AC%E4%BA%8C%E9%97%AE%E8%AF%81)
已知函数f(x)的定义域为【0,1】,且同时满足:(1)对任意x∈【0,1】总有f(x)≥2(2)f(1)=3(3)若x1≥0,x2≥0,且x1+x2≤1,则有f(x1+x2)≥f(x1)+f(x2)-2前两问我都会.第一问求出来f(0)=2,第二问证
已知函数f(x)的定义域为【0,1】,且同时满足:
(1)对任意x∈【0,1】总有f(x)≥2
(2)f(1)=3
(3)若x1≥0,x2≥0,且x1+x2≤1,则有f(x1+x2)≥f(x1)+f(x2)-2
前两问我都会.第一问求出来f(0)=2,第二问证明了函数在定义域内单增
第三问:数列{an}=(1/3)^(n-1),求证f(a1)+f(a2)+.f(an)≤3/2+2n-[1/2*3^(1-n)]
已知函数f(x)的定义域为【0,1】,且同时满足:(1)对任意x∈【0,1】总有f(x)≥2(2)f(1)=3(3)若x1≥0,x2≥0,且x1+x2≤1,则有f(x1+x2)≥f(x1)+f(x2)-2前两问我都会.第一问求出来f(0)=2,第二问证
f(a1)+f(a2)+.f(an)=f(1)+f(1/3)+...+f((1/3)^(n-1))
而1/3+1/9+...+(1/3)^(n-1)=(1-(1/3)^(n-1))/2
so easy