已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
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![已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值](/uploads/image/z/812983-31-3.jpg?t=%E5%B7%B2%E7%9F%A5x%3E0%2Cy%3E0%2C%E4%B8%94x%2B6y%3D5%E6%A0%B9%E5%8F%B7xy%2C%E6%B1%82%282x%2B%E6%A0%B9%E5%8F%B7xy-y%29%E5%88%86%E4%B9%8B%28x%2B%E6%A0%B9%E5%8F%B7xy%2B2y%29%E7%9A%84%E5%80%BC)
已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
x-5xy+6y=0
(√x-2√y)(√x-3√y)=0
所以√x=2√y,√x=3√y
x=4y或x=9y
原式=(8y)/(9y)=8/9或=(14y)/(20y)=7/10