已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
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![已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)](/uploads/image/z/8328276-36-6.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%9Ax%2F2%3Dy%2F3%3Dz%2F4%2C%E6%B1%82%EF%BC%88x2%2By2-z2-2xy%EF%BC%89%2F%EF%BC%88x2-y2%2Bz2-2xz%EF%BC%89%E9%99%A4%E4%BB%A5%EF%BC%88x2-y2-z2%2B2yz%29%2F%28x2%2By2-z2%2B2xy%29)
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
你就设,X=2M,Y=3M,Z=4M,
那原式就是····你自己往里代吧,接下来很简单了