若(ax²-2xy+y²)-(-ax²+bxy+2y²)=8x²-7xy-cy²成立,则a,b,c的值
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![若(ax²-2xy+y²)-(-ax²+bxy+2y²)=8x²-7xy-cy²成立,则a,b,c的值](/uploads/image/z/8460193-49-3.jpg?t=%E8%8B%A5%28ax%26%23178%3B-2xy%2By%26%23178%3B%29-%28-ax%26%23178%3B%2Bbxy%2B2y%26%23178%3B%29%3D8x%26%23178%3B-7xy-cy%26%23178%3B%E6%88%90%E7%AB%8B%2C%E5%88%99a%2Cb%2Cc%E7%9A%84%E5%80%BC)
若(ax²-2xy+y²)-(-ax²+bxy+2y²)=8x²-7xy-cy²成立,则a,b,c的值
若(ax²-2xy+y²)-(-ax²+bxy+2y²)=8x²-7xy-cy²成立,则a,b,c的值
若(ax²-2xy+y²)-(-ax²+bxy+2y²)=8x²-7xy-cy²成立,则a,b,c的值
解;2aX^2-(2+b)XY-Y^2=8X^2-7XY-cY^2
所以2a=8,2+b=7,1=c
a=4,b=5,c=1