(1+√2i)²-2(1+√2i)=
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![(1+√2i)²-2(1+√2i)=](/uploads/image/z/8639803-19-3.jpg?t=%EF%BC%881%2B%E2%88%9A2i%EF%BC%89%26%23178%3B-2%EF%BC%881%2B%E2%88%9A2i%EF%BC%89%3D)
(1+√2i)²-2(1+√2i)=
(1+√2i)²-2(1+√2i)=
(1+√2i)²-2(1+√2i)=
(1+√2i)²-2(1+√2i)
=1-2+2√2i-2-2√2i
=1-4
=-3;
原式=(1+√2i)(1+√2i-2)
=(√2i+1)(√2i-1)
=(√2i)²-1
=-2-1
=-3
(1+√2i)²-2(1+√2i)
=(1+√2i)((1+√2i)-2)
=(1+√2i)(-1+√2i)
=(-1)²-(√2i)²
=1+2
=3