初中数学题解答若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b-4ab²-20
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![初中数学题解答若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b-4ab²-20](/uploads/image/z/8865689-41-9.jpg?t=%E5%88%9D%E4%B8%AD%E6%95%B0%E5%AD%A6%E9%A2%98%E8%A7%A3%E7%AD%94%E8%8B%A5%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%882x%26%23178%3B%EF%BC%8Dax%EF%BC%8D1%2F3y%EF%BC%8B1%2F5%EF%BC%89%EF%BC%8D%EF%BC%881%2F2x%EF%BC%8D2y%EF%BC%8B1-bx%26%23178%3B%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%8Ex%E6%97%A0%E5%85%B3%2C%E6%B1%822a%26%23178%3Bb%E8%8B%A5%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%882x%26%23178%3B%EF%BC%8Dax%EF%BC%8D1%2F3y%EF%BC%8B1%2F5%EF%BC%89%EF%BC%8D%EF%BC%881%2F2x%EF%BC%8D2y%EF%BC%8B1%EF%BC%8Dbx%26%23178%3B%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%8Ex%E6%97%A0%E5%85%B3%EF%BC%8C%E6%B1%822a%26%23178%3Bb%EF%BC%8D4ab%26%23178%3B%EF%BC%8D20)
初中数学题解答若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b-4ab²-20
初中数学题解答若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b
若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b-4ab²-2007的值。
初中数学题解答若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b若代数式(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关,求2a²b-4ab²-20
(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)的值与x无关
(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)
=(2+b)x²-(a+1/2)x+5/3y-4/5
2+b=0 a+1/2=0
a=-1/2 b=-2
2a²b-4ab²-2007
=2(-1/2)^2*(-2)-4*(-1/2)(-2)^2-2007
=-1+8-2007
=-2000
(2x²-ax-1/3y+1/5)-(1/2x-2y+1-bx²)
=(2+b)x²-(a+1/2)x-(1/3-2)y-4/5
值与x无关
2+b=0 b=-2
a+1/2=0 a=-1/2
2a²b=-1
-2000
因为和x值无关,所以x的系数全为0.解得b=-2,a=-1/2