已知0<a<π/2<β<π,且cosa=3/5,sin(a+β)=-5/13求sinβ,cosβ,tanβ的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 13:40:16
![已知0<a<π/2<β<π,且cosa=3/5,sin(a+β)=-5/13求sinβ,cosβ,tanβ的值](/uploads/image/z/965891-11-1.jpg?t=%E5%B7%B2%E7%9F%A50%EF%BC%9Ca%EF%BC%9C%CF%80%2F2%EF%BC%9C%CE%B2%EF%BC%9C%CF%80%2C%E4%B8%94cosa%3D3%2F5%2Csin%EF%BC%88a%2B%CE%B2%EF%BC%89%3D-5%2F13%E6%B1%82sin%CE%B2%2Ccos%CE%B2%2Ctan%CE%B2%E7%9A%84%E5%80%BC)
已知0<a<π/2<β<π,且cosa=3/5,sin(a+β)=-5/13求sinβ,cosβ,tanβ的值
已知0<a<π/2<β<π,且cosa=3/5,sin(a+β)=-5/13求sinβ,cosβ,tanβ的值
已知0<a<π/2<β<π,且cosa=3/5,sin(a+β)=-5/13求sinβ,cosβ,tanβ的值
已知0<α<π/2<β<π,且cosα=3/5,sin(α+β)=-5/13
求sinβ,cosβ,tanβ的值
0<α<π/2<β<π
则sinα>0
sinβ>0
cosβ
假设β=b
π/2所以:πtana=4/3,tan(a+b)=5/12
tan(a+b)=(tana+tanb)/(1-tanatanb)
tanb=-33/56
cosb=-56/65
所以:cosβ=-56/65,tanβ=-33/56