(1)原式=4.25×4×5.24/4+1.52/4×4×2.25=17×1.31+0.38×9=20×1.31-3.93+0.38×10-0.38=26.2+3.8-4.31=30-4.31=25.69(2)原式共有998+1项,在前998项中,1-3=-2,5-7=-2……1993-1995=-2,这样差为-2的组有499组故原式=-2×499+1997=1997-2×50
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![(1)原式=4.25×4×5.24/4+1.52/4×4×2.25=17×1.31+0.38×9=20×1.31-3.93+0.38×10-0.38=26.2+3.8-4.31=30-4.31=25.69(2)原式共有998+1项,在前998项中,1-3=-2,5-7=-2……1993-1995=-2,这样差为-2的组有499组故原式=-2×499+1997=1997-2×50](/uploads/image/z/1073344-40-4.jpg?t=%281%29%E5%8E%9F%E5%BC%8F%3D4.25%C3%974%C3%975.24%2F4%EF%BC%8B1.52%2F4%C3%974%C3%972.25%3D17%C3%971.31%2B0.38%C3%979%3D20%C3%971.31-3.93%2B0.38%C3%9710-0.38%3D26.2%2B3.8-4.31%3D30-4.31%3D25.69%282%29%E5%8E%9F%E5%BC%8F%E5%85%B1%E6%9C%89998%2B1%E9%A1%B9%2C%E5%9C%A8%E5%89%8D998%E9%A1%B9%E4%B8%AD%2C1-3%3D-2%2C5-7%3D-2%E2%80%A6%E2%80%A61993-1995%3D-2%2C%E8%BF%99%E6%A0%B7%E5%B7%AE%E4%B8%BA-2%E7%9A%84%E7%BB%84%E6%9C%89499%E7%BB%84%E6%95%85%E5%8E%9F%E5%BC%8F%3D-2%C3%97499%2B1997%3D1997-2%C3%9750)
(1)原式=4.25×4×5.24/4+1.52/4×4×2.25=17×1.31+0.38×9=20×1.31-3.93+0.38×10-0.38=26.2+3.8-4.31=30-4.31=25.69(2)原式共有998+1项,在前998项中,1-3=-2,5-7=-2……1993-1995=-2,这样差为-2的组有499组故原式=-2×499+1997=1997-2×50
(1)原式=4.25×4×5.24/4+1.52/4×4×2.25
=17×1.31+0.38×9
=20×1.31-3.93+0.38×10-0.38
=26.2+3.8-4.31
=30-4.31
=25.69
(2)原式共有998+1项,在前998项中,
1-3=-2,5-7=-2……1993-1995=-2,这样差为-2的组有499组
故原式=-2×499+1997
=1997-2×500+2
=999
(3)原式=5.6×69.32+138.64/2×0.05×2+69.32×10×0.43
=5.6×69.32+69.32×0.1+69.32×4.3
=69.32×(5.6+0.1+4.3)
=69.32×10
=693.2
(4)原式=0.37×100×6×4×0.25+3×(8.75+28.25)
=37×6+37×3=37×9=37×10-37
=333
(1)原式=4.25×4×5.24/4+1.52/4×4×2.25=17×1.31+0.38×9=20×1.31-3.93+0.38×10-0.38=26.2+3.8-4.31=30-4.31=25.69(2)原式共有998+1项,在前998项中,1-3=-2,5-7=-2……1993-1995=-2,这样差为-2的组有499组故原式=-2×499+1997=1997-2×50
原式都是什么呀?
对
对
没有题目,不知道对错
第一题可以先约分再计算,简单点,答案是对的
对
如果对请解释每一步的做法。 最好是把长度设为X来做。即假设:细所以蜡烛燃烧了40分钟 这样会具有普遍性 不对对完对。