y=cos(x)2+√3cos(x)sin(x)的单调递增区间已知向量a,b,且向量a=(1,√3cos(x)),向量b+(cos(x)2,sin(x)),x属於R,定义:y=向量a·向量b.(1)求y关於x的函数解析式及其单调递增区间(2)若x属於闭区间(0,3.14
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 00:09:09
![y=cos(x)2+√3cos(x)sin(x)的单调递增区间已知向量a,b,且向量a=(1,√3cos(x)),向量b+(cos(x)2,sin(x)),x属於R,定义:y=向量a·向量b.(1)求y关於x的函数解析式及其单调递增区间(2)若x属於闭区间(0,3.14](/uploads/image/z/11500944-24-4.jpg?t=y%3Dcos%28x%292%2B%E2%88%9A3cos%28x%29sin%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa%2Cb%2C%E4%B8%94%E5%90%91%E9%87%8Fa%3D%EF%BC%881%2C%E2%88%9A3cos%28x%29%29%2C%E5%90%91%E9%87%8Fb%2B%EF%BC%88cos%28x%292%2Csin%28x%29%29%2Cx%E5%B1%9E%E6%96%BCR%2C%E5%AE%9A%E4%B9%89%EF%BC%9Ay%3D%E5%90%91%E9%87%8Fa%C2%B7%E5%90%91%E9%87%8Fb.%EF%BC%881%EF%BC%89%E6%B1%82y%E5%85%B3%E6%96%BCx%E7%9A%84%E5%87%BD%E6%95%B0%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%8F%8A%E5%85%B6%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%EF%BC%882%EF%BC%89%E8%8B%A5x%E5%B1%9E%E6%96%BC%E9%97%AD%E5%8C%BA%E9%97%B4%EF%BC%880%2C3.14)
y=cos(x)2+√3cos(x)sin(x)的单调递增区间已知向量a,b,且向量a=(1,√3cos(x)),向量b+(cos(x)2,sin(x)),x属於R,定义:y=向量a·向量b.(1)求y关於x的函数解析式及其单调递增区间(2)若x属於闭区间(0,3.14
y=cos(x)2+√3cos(x)sin(x)的单调递增区间
已知向量a,b,且向量a=(1,√3cos(x)),向量b+(cos(x)2,sin(x)),x属於R,定义:y=向量a·向量b.
(1)求y关於x的函数解析式及其单调递增区间
(2)若x属於闭区间(0,3.1415926……/2)闭区间,求函数y=f(x)的最大值、最小值及其相应的x的值.
cos(x)2是平方
y=cos(x)2+√3cos(x)sin(x)的单调递增区间已知向量a,b,且向量a=(1,√3cos(x)),向量b+(cos(x)2,sin(x)),x属於R,定义:y=向量a·向量b.(1)求y关於x的函数解析式及其单调递增区间(2)若x属於闭区间(0,3.14
y=cos(x)2+√3cos(x)sin(x)=(cos2x+1)/2+根号3sin2x/2
=1/2(cos2x+根号3sin2x)+1/2
=sin(2x+π/4)+1/2
2kπ-π/2≤2x+π/4≤2kπ+π/2
单调递增区间:kπ-3π/8≤x≤kπ+π/8
在[0,π/2]
x=π/8,y最大=3/2
x=π/2,y最小=(-根号2+1)/2
y=2cos x (sin x+cos x)
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
证明COS(X+Y)COS(X-Y)=COS^2X-SIN^2Y
证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y)
当cos^2x-cos^2y=√3/2时,求sin(x+y)×sin(x-y)
证明cos 2x cos x=1/2(cos x+cos 3x)
y=(cos x-2)/(cos x-1)的值域
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)
y=cos^2 x-cos x +1的值域y=cos^2 x+cos x +1的值域,
cos(x)看到这个 cos(x)-cos(y)=?
设f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π),其中ω>0,求函数y=f(x)的值域,请看问题补充f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π) =4(coswxcosπ/6+sinwxsinπ6)sinwx+cos2wx =2√3sinwxcoswx+2sin²wx+cos2wx =√3si
y =(cos^2) x - sin (3^x),求y'
y=cos(π/3-x)cos[π/2(x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性
y=(sin x + COS x)^2
y=4√2sin x cos x+cos 2x 的值域是
【高中数学】已知cos(x+y)=1/3,cos(x-y)=2/3,且0
已知cos(x+y)=1/3,cos(x-y)+2/3,且0
已知函数f(x) =√3cos(2x-y)-sin(2x-y) (0