汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 19:10:01
![汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13](/uploads/image/z/225715-67-5.jpg?t=%E6%B1%B6%E5%B7%9D%E5%9C%B0%E9%9C%87%2C%E9%9C%87%E5%90%8E2%E5%B0%8F%E6%97%B6%2C%E6%9F%90%E6%AD%A6%E8%AD%A6%E7%8E%87%E9%83%A8%E9%98%9F%E4%BB%8E+XX%E5%8E%BF%E5%87%BA%E5%8F%91+%E5%8E%BB%E8%90%A5%E6%95%91%2C13%E6%97%A5%E5%87%8C%E6%99%A81%EF%BC%9A15%E5%88%86%E5%8A%A8%E8%BA%AB%2C%E4%BD%86%E9%80%94%E4%B8%AD%E9%81%87%E5%88%B0%E4%BA%86%E9%BA%BB%E7%83%A6%2C%E4%BB%96%E4%BB%AC%E5%86%B3%E5%AE%9A%E6%AD%A5%E8%A1%8C%2C%E4%BD%86%E5%88%B0%E8%BE%BE%E7%90%86%E5%8E%BF%E5%90%8E%E5%9B%A0%E6%95%91%E4%BA%BA%E8%80%8C%E8%80%BD%E8%AF%AF%E4%BA%861%E5%B0%8F%E6%97%B6.%E9%9A%8F%E5%90%8E%2C%E5%85%88%E6%B4%BE%E9%81%A3%E5%88%86%E9%98%9F%E5%B0%86%E6%AD%A5%E8%A1%8C%E9%80%9F%E5%BA%A6%E6%8F%90%E9%AB%98%E4%BA%869%E5%88%86%E4%B9%8B1.%E4%BA%8E13)
汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13
汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13日23时15分到达汶川~
求先遣分队从理县到汶川的平均速度是多少?
我会加的!
还求 从开始到理县的时间 从理县到汶川的速度和时间 (这是表格)
从开始到理县是30千米,从理县到汶川是60千米
是求 从XX县到理县的时间 从理县到汶川的速度和时间
求先遣分队从 理县 到汶川的平均速度是多少?
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汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13
设先遣分队从理 到汶川的平均速度是X千米每时
用时22小时,但步行时间T=22-1=21小时
由题意列方程:(30/x)+[60/(x+x/9)]=21
解方程得:84/x=21
x=4千米每时
答:先遣分队从理 到汶川的平均速度是4千米每时.(不好意思刚看到题目,希望对有所帮助)