(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 23:18:02
![(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用](/uploads/image/z/2528245-37-5.jpg?t=%28x-10%29%2F%28x-11%29%2B%28x-16%29%2F%28x-17%29%3D%28x-12%29%2F%28x-13%29%2B%28x-14%29%2F%28x-15%29%E5%BF%AB%2C%E6%80%A5%E7%94%A8)
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
快,急用
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用
两边减去2
(x-10)/(x-11)-1+(x-16)/(x-17)-1=(x-12)/(x-13)-1+(x-14)/(x-15)-1
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(2x-28)/(x-11)(x-17)-(2x-28)/(x-13)(x-15)=0
(2x-28)[1/(x²-28x+187)-1/(x²-28x+195)=0
因为x²-28x+187≠x²-28x+195
所以2x-28=0
x=14
答:
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
1+1/(x-11)+1+1/(x-17)=1+1/(x-13)+1+1/(x-15)
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(x-17+x-11)/[(x-11)(x-17)]=(x-15+x-13)/[(x-13...
全部展开
答:
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
1+1/(x-11)+1+1/(x-17)=1+1/(x-13)+1+1/(x-15)
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(x-17+x-11)/[(x-11)(x-17)]=(x-15+x-13)/[(x-13)(x-15)]
(2x-28)/[(x-11)(x-17)]=(2x-28)/[(x-13)(x-15)]
所以:
2x-28=0或者(x-11)(x-17)=(x-13)(x-15)(无解)
所以:x=14
经检验,x=14是原分式方程的根
收起