化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-
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![化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-](/uploads/image/z/3678725-29-5.jpg?t=%E5%8C%96%E7%AE%80sin%28x%2B7%CF%80%2F4%29%2Bcos%28x-3%CF%80%2F4%EF%BC%89%E6%AD%A5%E9%AA%A4%E6%88%91%E5%B7%B2%E7%BB%8F%E6%89%BE%E5%88%B0%E6%92%92sin%28x%2B7%CF%80%2F4%29%2Bcos%28x-3%CF%80%2F4%29%3Dsin%28x%2B2%CF%80-%CF%80%2F4%29%2Bcos%28x-%CF%80%2B%CF%80%2F4%29%E6%88%91%E9%97%AE%E4%B8%8B%E8%BF%99%E4%B8%80%E6%AD%A5%E6%98%AF%E5%9C%A8%E5%B9%B2%E5%98%9B%3F%3Dsin%28x-%CF%80%2F4%29%2Bcos%5B-%28%CF%80-x-%CF%80%2F4%29%5D%3Dsin%28x-%CF%80%2F4%29%2Bcos%28%CF%80-x-%CF%80%2F4%29%3Dsin%28x-%CF%80%2F4%29-cos%28x%2B%CF%80%2F4%29%3Dsin%28x-%CF%80%2F4%29-cos%28x%2B%CF%80%2F2-)
化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-
化简sin(x+7π/4)+cos(x-3π/4)
步骤我已经找到撒
sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-π/4)=sin(x-π/4)-cos(π/2+x-π/4)=sin(x-π/4)+sin(x-π/4)=2sin(x-π/4)
sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?sin(x+2π-π/4为什么给以化成sin(x-π/4)
化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-
你好
Sin(x)的周期为2丌
即sin(x)=sin(x+2丌)
可以从正弦函数曲线上清楚的看见这种关系