已知数列满足a1=1,an-a(n-1)=n-1,求其通项
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已知数列满足a1=1,an-a(n-1)=n-1,求其通项
已知数列满足a1=1,an-a(n-1)=n-1,求其通项
已知数列满足a1=1,an-a(n-1)=n-1,求其通项
an-a(n-1)=n-1
a2-a1=1
a3-a2=2
a4-a3=3
;
an-a(n-1)=n-1
上式左右分别相加
an-a1=1+2+...+(n-1)
an-1=n(n-1)/2
an=(n²-n+2)/2
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