ansys求助:张弦桁架结构的三种单元:beam4、link8、link10,单元类型,实常数,还有材料特性ET,1,beam4R,1,2.060885e-2,4.33702e-4,4.33702e-4,0.032,0.032R,2,3.015929e-2,8.70095e-4,8.70095e-4,0.04,0.04MP,EX,1,206e9MP,DENS,1,7850ET,
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![ansys求助:张弦桁架结构的三种单元:beam4、link8、link10,单元类型,实常数,还有材料特性ET,1,beam4R,1,2.060885e-2,4.33702e-4,4.33702e-4,0.032,0.032R,2,3.015929e-2,8.70095e-4,8.70095e-4,0.04,0.04MP,EX,1,206e9MP,DENS,1,7850ET,](/uploads/image/z/6377892-60-2.jpg?t=ansys%E6%B1%82%E5%8A%A9%EF%BC%9A%E5%BC%A0%E5%BC%A6%E6%A1%81%E6%9E%B6%E7%BB%93%E6%9E%84%E7%9A%84%E4%B8%89%E7%A7%8D%E5%8D%95%E5%85%83%EF%BC%9Abeam4%E3%80%81link8%E3%80%81link10%2C%E5%8D%95%E5%85%83%E7%B1%BB%E5%9E%8B%2C%E5%AE%9E%E5%B8%B8%E6%95%B0%2C%E8%BF%98%E6%9C%89%E6%9D%90%E6%96%99%E7%89%B9%E6%80%A7ET%2C1%2Cbeam4R%2C1%2C2.060885e-2%2C4.33702e-4%2C4.33702e-4%2C0.032%2C0.032R%2C2%2C3.015929e-2%2C8.70095e-4%2C8.70095e-4%2C0.04%2C0.04MP%2CEX%2C1%2C206e9MP%2CDENS%2C1%2C7850ET%2C)
ansys求助:张弦桁架结构的三种单元:beam4、link8、link10,单元类型,实常数,还有材料特性ET,1,beam4R,1,2.060885e-2,4.33702e-4,4.33702e-4,0.032,0.032R,2,3.015929e-2,8.70095e-4,8.70095e-4,0.04,0.04MP,EX,1,206e9MP,DENS,1,7850ET,
ansys求助:张弦桁架结构的三种单元:beam4、link8、link10,单元类型,实常数,还有材料特性
ET,1,beam4
R,1,2.060885e-2,4.33702e-4,4.33702e-4,0.032,0.032
R,2,3.015929e-2,8.70095e-4,8.70095e-4,0.04,0.04
MP,EX,1,206e9
MP,DENS,1,7850
ET,2,link8
R,3,2.74889e-3,0
R,4,5.34071e-3,0
R,5,1.15108e-2,0
R,6,5.44202e-3,0
MP,EX,2,206e9
MP,DENS,2,7850
ET,3,link10
R,7,3.08479e-3,2.159e-3
MP,EX,3,196e9
MP,DENS,3,7850
如何将不同单元的实常数写在一起,而又能说明这些是常数对应的是所对应的单元类型,
ansys求助:张弦桁架结构的三种单元:beam4、link8、link10,单元类型,实常数,还有材料特性ET,1,beam4R,1,2.060885e-2,4.33702e-4,4.33702e-4,0.032,0.032R,2,3.015929e-2,8.70095e-4,8.70095e-4,0.04,0.04MP,EX,1,206e9MP,DENS,1,7850ET,
你的这个问题很混乱,但我明白你的意思.你上面那样写是可以的,你就怕的是具体的单元对应哪个实常数吧,在你建立有限元模型的时候,你先定义要用那个单元和实常数,这样的话该单元自然就用你定义的单元和常数.以你上面单位为例:
TYPE,1
REAL,1
MAT,1
.
.
.
TYPE,1
REAL,2
MAT,1
.
.
.
TYPE,2
REAL,3
MAT,1
.
.
.
TYPE,2
REAL,4
MAT,1
.
.
.
其余以此类推,我想你应该明白我的意思了.不明白的还联系我crfsdi_lx@163.com,我是搞桥梁勘察设计的.