第N次上数学理解...懂的进来分解因式:ac-bc+a²-b²= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!】=(a-b)(a+b+c)类似这个……(x+p)²-(x+q)²=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】=(2x+p+q)(p-q)
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![第N次上数学理解...懂的进来分解因式:ac-bc+a²-b²= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!】=(a-b)(a+b+c)类似这个……(x+p)²-(x+q)²=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】=(2x+p+q)(p-q)](/uploads/image/z/7012785-57-5.jpg?t=%E7%AC%ACN%E6%AC%A1%E4%B8%8A%E6%95%B0%E5%AD%A6%E7%90%86%E8%A7%A3...%E6%87%82%E7%9A%84%E8%BF%9B%E6%9D%A5%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9Aac-bc%2Ba%26sup2%3B-b%26sup2%3B%3D+c%28ab%29%2B%28a%2Bb%29%28a-b%29%E3%80%90%E8%BF%99%E9%87%8C%E6%98%AF%E6%80%8E%E6%A0%B7%E5%BC%84%E5%87%BA%E4%B8%8B%E4%B8%80%E6%AD%A5%E7%9A%84%21%E3%80%91%3D%28a-b%29%28a%2Bb%2Bc%29%E7%B1%BB%E4%BC%BC%E8%BF%99%E4%B8%AA%E2%80%A6%E2%80%A6%28x%2Bp%29%26sup2%3B-%28x%2Bq%29%26sup2%3B%3D%5B%28x%2Bp%29%2B%28x%2Bq%29%5D%5B%28x%2Bp%29-%28x%2Bq%29%5D%E3%80%90%E8%B7%9F%E4%B8%8A%E9%9D%A2%E4%B8%80%E6%A0%B7%E3%80%91%3D%282x%2Bp%2Bq%29%28p-q%29)
第N次上数学理解...懂的进来分解因式:ac-bc+a²-b²= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!】=(a-b)(a+b+c)类似这个……(x+p)²-(x+q)²=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】=(2x+p+q)(p-q)
第N次上数学理解...懂的进来
分解因式:ac-bc+a²-b²
= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!】
=(a-b)(a+b+c)
类似这个……
(x+p)²-(x+q)²
=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】
=(2x+p+q)(p-q)
第N次上数学理解...懂的进来分解因式:ac-bc+a²-b²= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!】=(a-b)(a+b+c)类似这个……(x+p)²-(x+q)²=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】=(2x+p+q)(p-q)
ac-bc+a²-b²
= c(a-b)+(a+b)(a-b)【应该是a-b,你写错了,c(a-b)是提公因式,a+b)(a-b)平方差公式,】
=(a-b)(a+b+c)(提取a+b)
类似这个……
(x+p)²-(x+q)²
=[(x+p)+(x+q)][(x+p)-(x+q)]【跟上面一样】
=(2x+p+q)(p-q)
很明显你这步c(ab)+(a+b)(a-b)应该为c(a-b)+(a+b)(a-b)然后提公因式
而下面那个化简就行了。兰州,你又马虎了啊。O(∩_∩)O~
= c(ab)+(a+b)(a-b)【这里是怎样弄出下一步的!!】
=(a-b)(a+b+c)
---->有错误,应该是c(a-b)+(a+b)(a-b)=(a-b)(c+a+b)
去掉括号,合并x