设实数x,y,满足y+x^2=0,0<a<1,求证loga(a^x+a^y)<1/8+loga2
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![设实数x,y,满足y+x^2=0,0<a<1,求证loga(a^x+a^y)<1/8+loga2](/uploads/image/z/7040341-37-1.jpg?t=%E8%AE%BE%E5%AE%9E%E6%95%B0x%2Cy%2C%E6%BB%A1%E8%B6%B3y%2Bx%5E2%3D0%2C0%EF%BC%9Ca%EF%BC%9C1%2C%E6%B1%82%E8%AF%81loga%28a%5Ex%2Ba%5Ey%29%EF%BC%9C1%2F8%2Bloga2)
设实数x,y,满足y+x^2=0,0<a<1,求证loga(a^x+a^y)<1/8+loga2
设实数x,y,满足y+x^2=0,0<a<1,求证loga(a^x+a^y)<1/8+loga2
设实数x,y,满足y+x^2=0,0<a<1,求证loga(a^x+a^y)<1/8+loga2
∵y+x^2=0
∴x+y=x-x^2=-(x-2)^2+1/4≤1/4
∴x+y的最大值=1/4
∵0
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