Lim(arctanx)ln(1-x)求极限是为什么x默认趋近于0+×→0即Limln(1-x)ln(arctanx)×→0+
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Lim(arctanx)ln(1-x)求极限是为什么x默认趋近于0+×→0即Limln(1-x)ln(arctanx)×→0+
Lim(arctanx)ln(1-x)求极限是为什么x默认趋近于0+
×→0
即
Limln(1-x)ln(arctanx)
×→0+
Lim(arctanx)ln(1-x)求极限是为什么x默认趋近于0+×→0即Limln(1-x)ln(arctanx)×→0+
如果×→0-,arctanx<0,ln无意义
因为ln后面的数要大于零,讨论小于零的情况没意义
所以求x→0是只讨论右极限x→0+
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